Determine Output:
void main()
{
char *p;
printf("%d %d", sizeof(*p), sizeof(p));
}
void main()
{
char *p;
printf("%d %d", sizeof(*p), sizeof(p));
}A. 1 1
B. 1 2
C. 2 1
D. 2 2
Answer: Option B
Solution (By Examveda Team)
The sizeof() operator gives the number of bytes taken by its operand. P is a character pointer, which needs one byte for storing its value (a character). Hence sizeof(*p) gives a value of 1. Since it needs two bytes to store the address of the character pointer sizeof(p) gives 2.
This Question Belongs to C Program >> C Miscellaneous
size of pointer is 8 bytes for 64 bit OS
size of pointer is 4 bytes for 32 bit OS
when i executed this code, it gave an output :1 4
When I execute the code, I got output as 1 8