Determine Output:
void main()
{
int c = - -2;
printf("c=%d", c);
}
void main()
{
int c = - -2;
printf("c=%d", c);
}A. 1
B. -2
C. 2
D. Error
Answer: Option C
Solution(By Examveda Team)
Here unary minus (or negation) operator is used twice. Same maths rule applies, ie. minus * minus= plus.
Note: However you cannot give like --2. Because -- operator can only be applied to variables as a decrement operator (eg., i--). 2 is a constant and not a variable.
This Question Belongs to C Program >> C Miscellaneous
Determine output:
void main()
{
int const *p=5;
printf("%d", ++(*p));
}
A. 6
B. 5
C. Garbage Value
D. Compiler Error
A. mmm nnn aaa
B. mmmm nnnn aaaa
C. Compiler Error
D. None of These
A. I hate Examveda
B. I love Examveda
C. Error
D. None of These
Determine Output:
void main()
{
static int var = 5;
printf("%d ", var--);
if(var)
main();
}
A. 5 5 5 5 5
B. 5 4 3 2 1
C. Infinite Loop
D. None of These
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