Determine Output #define int char void main() int i = 65

Determine Output #define int char void main() int i = 65...

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Determine Output:

#define int char
void main()
{
      int i = 65;
      printf("sizeof(i)=%d", sizeof(i));
}

A. sizeof(i)=2

B. sizeof(i)=1

C. Compiler Error

D. None of These

Answer: Option B

Solution (By Examveda Team)

Since the #define replaces the string int by the macro char.

This Question Belongs to C Program >> C Miscellaneous

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Comments (3)

Mainak Karmakar:

4 years ago

according to the size of byte that takes "sizeof" to store given data is 1. so the answer should be one
Tararam Goyal:

7 years ago

output of the above code is depends upon compiler ( vary compiler to compiler) according to option correct option is "sizeof(i)=2"
Camadi Chanal:

8 years ago

Please explain the answer sir

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Determine Output:

`#define int char void main() { int i = 65; printf("sizeof(i)=%d", sizeof(i)); }`

Solution (By Examveda Team)

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Comments (3)

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