Determine output:
public class Test{
public static void main(String args[]){
MyClass obj = new MyClass();
obj.val = 1;
obj.call(obj);
System.out.println(obj.val);
}
}
class MyClass{
public int val;
public void call(MyClass ref){
ref.val++;
}
}
public class Test{
public static void main(String args[]){
MyClass obj = new MyClass();
obj.val = 1;
obj.call(obj);
System.out.println(obj.val);
}
}
class MyClass{
public int val;
public void call(MyClass ref){
ref.val++;
}
}A. 1
B. 2
C. 3
D. Compilation Error
E. None of these
Answer: Option B
Solution (By Examveda Team)
Step-by-step breakdown:1. The main method in the Test class creates an instance of MyClass called obj.
2. The val field of obj is set to 1 with obj.val = 1.
3. The call method is invoked on obj with obj itself as the argument: obj.call(obj).
4. Inside the call method, the val field of the passed MyClass instance (ref) is incremented by 1 using ref.val++. Since ref refers to obj, this increments obj.val from 1 to 2.
5. Finally, System.out.println(obj.val) prints the value of obj.val, which is now 2.
Therefore, the output of the program is 2.
This Question Belongs to Java Program >> Constructors And Methods
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Initially, obj.val is set to 1.
The call method increments obj.val by 1, making it 2.
The final output printed to the console is 2.
Pls explain this program
how