Determine output:

class A{
        public static void main(String args[]){
	        int x;
 	        x = 10;
	        if(x == 10){
		        int y = 20;
		        System.out.print("x and y: "+ x + " " + y);
		        y = x*2;
	        }
	        y = 100;
	        System.out.print("x and y: " + x + " " + y);
        }
}

Solution(By Examveda Team)

The code defines a class A with a main method.
Inside the main method:
- An integer variable x is declared and assigned the value 10.
- There's an if statement that checks if x is equal to 10. This condition is true.
- Inside the if block:
- Another integer variable y is declared and assigned the value 20.
- The program prints "x and y: 10 20" using System.out.print.
- The value of y is updated to x * 2, which is 20.
- Outside the if block:
- The program attempts to update the value of y to 100. However, this line causes a compilation error because the variable y was declared inside the if block and is not accessible outside of it.
- The program also attempts to print "x and y: 10 100". This line also causes a compilation error because the variable y is not in scope at this point.

So, the correct answer is "Error" because the code contains compilation errors due to the variable y being declared within the if block and not being accessible outside of it. The program cannot find the symbol y outside of the if block, leading to compilation errors.