Dev can hit a target 3 times in 6 shots pawan can hit the target 2 times in 6 shots and Lakhan can hit the target 4 times in 4 shots. What is the probability that at least 2 shots hit the target -
A. $$\frac{{2}}{{3}}$$
B. $$\frac{{1}}{{3}}$$
C. $$\frac{{1}}{{2}}$$
D. None of these
Answer: Option A
Solution(By Examveda Team)
Probability of hitting the target:Dev can hit target ⇒ $$\frac{{3}}{{6}}$$ =$$\frac{{1}}{{2}}$$
Lakhan can hit target =$$\frac{{4}}{{4}}$$ = 1
Pawan can hit target = $$\frac{{2}}{{6}}$$ = $$\frac{{1}}{{3}}$$
Required probability that at least 2 shorts hit target
$$\eqalign{ & = \frac{1}{2} \times \frac{2}{3} + \frac{1}{2} \times \frac{1}{3} + \frac{1}{2} \times \frac{1}{3} \cr & = \frac{1}{3} + \frac{1}{6} + \frac{1}{6} \cr & = \frac{4}{6} \cr & = \frac{2}{3} \cr} $$
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Comments ( 3 )
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
Required probability
=P(A) P(B) P(
C
ˉ
)+P(A) P(
B
ˉ
) P(C)+P(
A
ˉ
) P(B) P(C)+P(A) P(B) P(C)
=
2
1
×
3
1
×0+
2
1
×
3
2
×1+
2
1
×
3
1
×1+
2
1
×
3
1
×1
=
3
1
+
6
1
+
6
1
=
3
2
Logic behind the 2nd step is not clear. Can we get the elaborates form please?
Don’t understand