ExamVeda
Login
Home
This question belongs to Arithmetic Ability Probability
Probability
?

Dev can hit a target 3 times in 6 shots pawan can hit the target 2 times in 6 shots and Lakhan can hit the target 4 times in 4 shots. What is the probability that at least 2 shots hit the target -

Answer & Solution
Correct Answer: Option A
Probability of hitting the target:
Dev can hit target ⇒ $$\frac{{3}}{{6}}$$ =$$\frac{{1}}{{2}}$$
Lakhan can hit target =$$\frac{{4}}{{4}}$$  = 1
Pawan can hit target = $$\frac{{2}}{{6}}$$  = $$\frac{{1}}{{3}}$$
Required probability that at least 2 shorts hit target
$$\eqalign{ & = \frac{1}{2} \times \frac{2}{3} + \frac{1}{2} \times \frac{1}{3} + \frac{1}{2} \times \frac{1}{3} \cr & = \frac{1}{3} + \frac{1}{6} + \frac{1}{6} \cr & = \frac{4}{6} \cr & = \frac{2}{3} \cr} $$
Examveda
Question posted by Examveda
Community

Join the Discussion

3 Comments
Shuvo Hasan
Shuvo Hasan 5 years ago
Required probability
=P(A) P(B) P(
C
ˉ
)+P(A) P(
B
ˉ
) P(C)+P(
A
ˉ
) P(B) P(C)+P(A) P(B) P(C)
=
2
1
​
×
3
1
​
×0+
2
1
​
×
3
2
​
×1+
2
1
​
×
3
1
​
×1+
2
1
​
×
3
1
​
×1

=
3
1
​
+
6
1
​
+
6
1
​
=
3
2
​
Madhab Kumar
Madhab Kumar 6 years ago
Logic behind the 2nd step is not clear. Can we get the elaborates form please?
Md. Mubarak
Md. Mubarak 7 years ago
Don’t understand