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Dev can hit a target 3 times in 6 shots pawan can hit the target 2 times in 6 shots and Lakhan can hit the target 4 times in 4 shots. What is the probability that at least 2 shots hit the target -

A. $$\frac{{2}}{{3}}$$

B. $$\frac{{1}}{{3}}$$

C. $$\frac{{1}}{{2}}$$

D. None of these

Answer: Option A

Solution(By Examveda Team)

Probability of hitting the target:
Dev can hit target ⇒ $$\frac{{3}}{{6}}$$ =$$\frac{{1}}{{2}}$$
Lakhan can hit target =$$\frac{{4}}{{4}}$$  = 1
Pawan can hit target = $$\frac{{2}}{{6}}$$  = $$\frac{{1}}{{3}}$$
Required probability that at least 2 shorts hit target
$$\eqalign{ & = \frac{1}{2} \times \frac{2}{3} + \frac{1}{2} \times \frac{1}{3} + \frac{1}{2} \times \frac{1}{3} \cr & = \frac{1}{3} + \frac{1}{6} + \frac{1}{6} \cr & = \frac{4}{6} \cr & = \frac{2}{3} \cr} $$

This Question Belongs to Arithmetic Ability >> Probability

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Comments ( 3 )

  1. Shuvo Hasan
    Shuvo Hasan :
    2 years ago

    Required probability
    =P(A) P(B) P(
    C
    ˉ
    )+P(A) P(
    B
    ˉ
    ) P(C)+P(
    A
    ˉ
    ) P(B) P(C)+P(A) P(B) P(C)
    =
    2
    1

    ×
    3
    1

    ×0+
    2
    1

    ×
    3
    2

    ×1+
    2
    1

    ×
    3
    1

    ×1+
    2
    1

    ×
    3
    1

    ×1

    =
    3
    1

    +
    6
    1

    +
    6
    1

    =
    3
    2

  2. Madhab Kumar
    Madhab Kumar :
    3 years ago

    Logic behind the 2nd step is not clear. Can we get the elaborates form please?

  3. Md. Mubarak
    Md. Mubarak :
    4 years ago

    Don’t understand

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