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Efficiency of a Carnot engine is given as 80%. If the cycle direction be reversed, what will be the value of C.O.P. of reversed Carnot Cycle?
Answer & Solution
Correct Answer:
Option
D
Efficiency of a Carnot engine is given as 80% or $$\eta $$ = 0.80
If the cycle direction be reversed
The relation between the effecicy and C.O.P. is defined by formula
$${\text{C}}{\text{.O}}{\text{.P}}{\text{.}} = \frac{{1 - \eta }}{\eta } = \frac{{1 - 0.80}}{{0.80}} = 0.25$$
If the cycle direction be reversed
The relation between the effecicy and C.O.P. is defined by formula
$${\text{C}}{\text{.O}}{\text{.P}}{\text{.}} = \frac{{1 - \eta }}{\eta } = \frac{{1 - 0.80}}{{0.80}} = 0.25$$
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