Eight consecutive numbers are given. If the average of the two numbers that appear in the middle is 6, then the sum of the eight given numbers is :

Let eight consecutive numbers are
= 1, 2, 3, 4, 5, 6, 7, 8 sum
= 36 units two middle numbers are
= 4 + 5
= 9 units
Average of two middle numbers = 6 (Given)
Sum of two middle numbers = 6 × 2 = 12
∴ 9 units → 12
1 unit → $$\frac{12}{9}$$
∴ 36 units → $$\frac{12}{9}$$ × 36 = 48
∴ Sum of all consecutive number = 48