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11
Two series resistors are connected to an ac source. If there are 7.5 V rms across one resistor and 4.2 V rms across the other, the peak source voltage is
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Answer & Solution
Answer: Option A
Solution:
Understanding the Problem:
We have two resistors in series connected to an AC voltage source.
We know the RMS (Root Mean Square) voltage across each resistor.
We need to find the peak voltage of the source.
Key Concepts:
RMS Voltage: This is the effective voltage of an AC signal, equivalent to a DC voltage that would produce the same heating effect.
Peak Voltage: This is the maximum voltage reached by the AC signal during each cycle. The relationship between peak voltage (Vpeak) and RMS voltage (Vrms) is: Vpeak = Vrms * √2
Series Circuit: In a series circuit, the current is the same through all components. The voltages across the resistors add up to the source voltage.
Steps to Solve:
1. Find the total RMS voltage: Since the resistors are in series, the total RMS voltage is the sum of the RMS voltages across each resistor. So, Vrms(total) = 7.5 V + 4.2 V = 11.7 V
2. Calculate the peak voltage: Use the formula Vpeak = Vrms * √2. So, Vpeak = 11.7 V * √2 ≈ 11.7 V * 1.414 ≈ 16.54 V
Therefore, the correct answer is Option A: 16.54 V
12
A 1 kHz signal has a period of 1 ms.
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Answer & Solution
Answer: Option A
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13
A sine wave with a period of 4 ms is changing at a faster rate than a sine wave with a period of
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Answer: Option A
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14
The instantaneous value is the voltage or current value of a waveform at its peak.
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Answer: Option B
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15
A signal with a 400 µs period has a frequency of
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Answer & Solution
Answer: Option B
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16
A sinusoidal current has an rms value of 14 mA. The peak-to-peak value is
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Answer & Solution
Answer: Option C
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17
If the peak of a sine wave is 13 V, the peak-to-peak value is
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Answer & Solution
Answer: Option C
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18
The conductive loop on the rotor of a simple two-pole, single-phase generator rotates at a rate of 400 rps. The frequency of the induced output voltage is
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Answer & Solution
Answer: Option C
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19
A sine wave with an rms value of 12 V is riding on a dc level of 18 V. The maximum value of the resulting waveform is
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Answer & Solution
Answer: Option C
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20
Average value of a sine wave is 0.707 times the peak value.
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Answer & Solution
Answer: Option B
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