ExamVeda
Login
Home
21
A 50 kW carrier is to be amplitude modulated to a level of 85%. What is the carrier power after modulation?
Discuss
Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
22
The major advantage of FM over AM is ___________
Discuss
Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
23
In an AM wave, the majority of the power is in ___________
Discuss
Answer & Solution
Answer: Option C
No explanation is given for this question. Let's Discuss on Board
24
As the modulation level is increased, the carrier power ___________
Discuss
Answer & Solution
Answer: Option B
No explanation is given for this question. Let's Discuss on Board
25
Modulation refers to a low-frequency signal controlling the ___________
Discuss
Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board
26
In a radio receiver, noise is generally developed at ___________
Discuss
Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board
27
The diode detector in an AM radio receiver is usually found ___________
Discuss
Answer & Solution
Answer: Option C
No explanation is given for this question. Let's Discuss on Board
28
The function of ferrite antenna is to ___________
Discuss
Answer & Solution
Answer: Option C
No explanation is given for this question. Let's Discuss on Board
29
If Amin = 40 and Amax = 60, what is the percentage of modulation?
Discuss
Answer & Solution
Answer: Option A
Solution:
The correct answer is Option A: 20%.
Here's why:
Modulation percentage in Amplitude Modulation (AM) tells us how much the amplitude of the carrier signal changes.
It's calculated using the formula: Modulation Percentage = [(Amax - Amin) / (Amax + Amin)] * 100
Where:
Amax is the maximum amplitude of the modulated signal.
Amin is the minimum amplitude of the modulated signal.
In this problem:
Amax = 60
Amin = 40
So, let's plug in the values:
Modulation Percentage = [(60 - 40) / (60 + 40)] * 100
Modulation Percentage = [20 / 100] * 100
Modulation Percentage = 0.2 * 100
Modulation Percentage = 20%
Therefore, the percentage of modulation is 20%.
30
The signal voltage induced in the aerial of a radio receiver is of the order of ___________
Discuss
Answer & Solution
Answer: Option B
No explanation is given for this question. Let's Discuss on Board