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Parallel Circuits MCQ Questions & Answers | Electrical Engineering

Learn Parallel Circuits MCQ questions & answers are available for a Electrical Engineering students to clear GATE exams, various technical interview, competitive examination, and another entrance exam. Parallel Circuits MCQ question is the important chapter for a Electrical Engineering and GATE students. Page-2 section-1

11
An ammeter has an internal resistance of 50 Ω. The meter movement itself can handle up to 1 mA. If 10 mA is applied to the meter, the shunt resistor, RSH1, is approximately
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Answer & Solution
Answer: Option B
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12
In a five-branch parallel circuit, there are 12 mA of current in each branch. If one of the branches opens, the current in each of the other four branches is
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Answer: Option B
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13
Four 8 Ω speakers are connected in parallel to the output of an audio amplifier. If the maximum voltage to the speakers is 12 V, the amplifier must be able to deliver to the speakers
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Answer: Option D
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14
In a certain three-branch parallel circuit, R1 has 12 mA through it, R2 has 15 mA through it, and R3 has 25 mA through it. After measuring a total of 27 mA, you can say that
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Answer: Option A
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15
A 470 Ω resistor, a 220 Ω resistor, and a 100 Ω resistor are all in parallel. The total resistance is approximately
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Answer: Option C
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16
Total power in a parallel circuit is found by adding up the power of all the individual resistors.
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Answer: Option A
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17
Four resistors are connected in parallel. Fifteen mA flows through resistor R. If the second resistor is 2R, the third resistor 3R, and the fourth resistor 4R, the total current in the circuit is
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Answer: Option D
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18
The following currents are measured in the same direction in a three-branch parallel circuit: 200 mA, 340 mA, and 700 mA. The value of the current into the junction of these branches is
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Answer: Option C
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19
Three lights are connected in parallel across a 120 volt source. If one light burns out,
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Answer: Option D
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20
Four resistors of equal value are connected in parallel. If the total voltage is 15 V and the total resistance is 600 Ω, the current through each parallel resistor is
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Answer & Solution
Answer: Option C
Solution:
Understanding the Problem:
We have a parallel circuit with four identical resistors.
We know the total voltage across the parallel combination and the total equivalent resistance.
We need to find the current flowing through each individual resistor.

Key Concepts:
In a parallel circuit, the voltage across each branch is the same.
Ohm's Law: Voltage (V) = Current (I) x Resistance (R), or I = V/R
Step-by-Step Solution:
1. Find the total current (Itotal): Using Ohm's Law for the entire circuit, Itotal = Vtotal / Rtotal = 15 V / 600 Ω = 0.025 A = 25 mA
2. Find the resistance of each resistor (Reach): Since the resistors are in parallel and identical, the total resistance is related to the individual resistance by Rtotal = Reach / N (where N is the number of resistors).
Therefore, Reach = Rtotal * N = 600 Ω * 4 = 2400 Ω
3. Find the current through each resistor (Ieach): Since the voltage across each resistor is the same as the total voltage (15 V), we can use Ohm's Law again: Ieach = Veach / Reach = 15 V / 2400 Ω = 0.00625 A = 6.25 mA

Therefore, the correct answer is:
Option C: 6.25 mA