Equal masses of oxygen, hydrogen and methane are kept under identical conditions. The ratio of the volumes of gases will be

Solution (By Examveda Team)

Convert the mass into moles (use the formula n=m/Mr)
m = mass and Mr = Molecular weights
Molecular weights are 32(Oxygen), 2(Hydrogen), and 16(Methane), respectively.
Since the masses are equal, you can take the mass as x. So, the number of moles would be:
n(O2) = x/32
n(H2) = x/2
n(CH4) = x/16
The ratio of their volumes is (O₂) : (H₂) : (CH₄) = 1 : 16 : 2