Equal masses of oxygen, hydrogen and methane are kept under identical conditions. The ratio of the volumes of gases will be

A. 2 : 16 : 2

B. 2 : 16 : 1

C. 1 : 16 : 2

D. 1 : 1 : 1

Answer: Option C

Solution(By Examveda Team)

Convert the mass into moles (use the formula n=m/Mr)
m = mass and Mr = Molecular weights
Molecular weights are 32(Oxygen), 2(Hydrogen), and 16(Methane), respectively.
Since the masses are equal, you can take the mass as x. So, the number of moles would be:
n(O2) = x/32
n(H2) = x/2
n(CH4) = x/16
The ratio of their volumes is (O₂) : (H₂) : (CH₄) = 1 : 16 : 2