Esterification of the acid P with the alcohol Q will give

A. only one enantiomer
B. a mixture of diastereomers
C. a mixture of enantiomers
D. only one diastereomer
Answer: Option A
A. CH3C$${\text{O}}_2^ - $$ > CH3O- > C6H5O- > N$${\text{O}}_3^ - $$
B. CH3O- > N$${\text{O}}_3^ - $$ > C6H5O- > CH3C$${\text{O}}_2^ - $$
C. CH3O- > C6H5O- > CH3C$${\text{O}}_2^ - $$ > N$${\text{O}}_3^ - $$
D. C6H5O- > CH3O- > N$${\text{O}}_3^ - $$ > CH3C$${\text{O}}_2^ - $$
The most appropriate sequence of the reactions for carrying out the following conversion
is
A. (i) peracid, (ii) H+, (iii) Zn/dil.HCl
B. (i) Alkaline KMnO4, (ii) NalO4, (iii) N2H4/KOH
C. (i) Alkaline KMnO4, (ii) H+, (iii) Zn/dil.HCl
D. (i) O3/Me2S, (ii) NaOEt, (iii) N2H4/KOH
Conversion of Ph-NH2 into Ph-CN can be accomplished by
A. reaction with sodium cyanide in the presence of nickel catalyst
B. reaction with chloroform and sodium hydroxide
C. diazotisation followed by reaction with CuCN
D. reaction with ethyl formate followed by thermolysis
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