Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
A. 4
B. 7
C. 9
D. 13
Answer: Option A
Solution (By Examveda Team)
Required number= H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
This Question Belongs to Arithmetic Ability >> Problems On H.C.F And L.C.M
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Nice
Can you please briefly explain it
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To find the greatest number that will divide x, y and z leaving the same remainder in each case. (A) When the value of remainder r is given:
Required number = H.C.F. of (x – r), (y – r) and (z – r).
(B) When the value of remainder is not given:
Required number = H.C.F. of |(x – y)|, |(y – z)| and |(z – x)|
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Why do you subtract only 43 from other numbers???
Can you please briefly explain it