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Find the principal if the interest compounded at the rate of 10% per annum for two years is Rs. 420.

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Correct Answer: Option C
$$\eqalign{ & {\text{Given}}, \cr & {\text{Compound}}\,{\text{rate}},\,R = 10\% \,{\text{per}}\,{\text{annum}} \cr & {\text{Time}} = 2\,{\text{years}} \cr & CI - Rs.\,420 \cr & {\text{Let}}\,P\,{\text{be}}\,{\text{the}}\,{\text{required}}\,{\text{principal}} \cr & A = \left( {P + CI} \right) \cr & {\text{Amount}},A = \left\{ {P \times {{\left[ {1 + \left( {\frac{R}{{100}}} \right)} \right]}^n}} \right\} \cr & \left( {P + CI} \right) = \left\{ {P \times {{\left[ {1 + \frac{{10}}{{100}}} \right]}^2}} \right\} \cr & \left( {P + 420} \right) = P \times {\left[ {\frac{{11}}{{10}}} \right]^2} \cr & P - 1.21P = - 420 \cr & 0.21P = 420 \cr & {\text{Hence}},P = \frac{{420}}{{0.21}} = Rs.\,2000 \cr} $$
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2 Comments
Ahnaf Shahad
Ahnaf Shahad 2 years ago
@Darshan Sharma

here, p(1+r)^n -p
Or, p(1+10÷100)^2 -p
Or, p(1+0.1)^2 -p
Or, p(1.1)^2 -p
Or, p×1.21 -p.... [ 1.1^2=1.21]
Darshan Sharma
Darshan Sharma 3 years ago
How this 1.21 is come if we divide 11/10 we obtain 1.1