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First order perturbation correction $$\Delta \varepsilon _n^{\left( 1 \right)}$$  to energy level $${\varepsilon _n}$$ of a simple harmonic oscillator due to the anharmonicity perturbation $$\gamma {x^3}$$ is given by

A. $$\Delta \varepsilon _n^{\left( 1 \right)} = \gamma $$

B. $$\Delta \varepsilon _n^{\left( 1 \right)} = {\gamma ^2}$$

C. $$\Delta \varepsilon _n^{\left( 1 \right)} = {\gamma ^{ - 1}}$$

D. $$\Delta \varepsilon _n^{\left( 1 \right)} = 0$$

Answer: Option D


This Question Belongs to Engineering Chemistry >> Atomic Structure

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