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Five inductors are connected in series. The lowest value is 8 µH. If the value of each inductor is twice that of the preceding one, and if the inductors are connected in order of ascending values, the total inductance is

A. 8 H

B. 32 µH

C. 64 µH

D. 248 µH

Answer: Option D


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Comments ( 2 )

  1. Ameer Ali
    Ameer Ali :
    4 years ago

    8 16 32 64 128

    Inductance in series=8+16+32+64+128=248 microhenry

  2. Sameer Singh
    Sameer Singh :
    6 years ago

    how????

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