Five inductors are connected in series. The lowest value is 8 µH. If the value of each inductor is twice that of the preceding one, and if the inductors are connected in order of ascending values, the total inductance is
A. 8 H
B. 32 µH
C. 64 µH
D. 248 µH
Answer: Option D

8 16 32 64 128
Inductance in series=8+16+32+64+128=248 microhenry
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