For a bipolar junction transistor if the current amplification factor and...

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For a bipolar junction transistor, if the current amplification factor and cut-off frequency in the CB mode are α_CB and fα_CB respectively, then the cut-off frequency in the CE mode is equal to

A. $${\text{f}}{\alpha _{{\text{CB}}}}$$

B. $${\text{f}}{\alpha _{{\text{CB}}}}\left( {1 - {\alpha _{{\text{CB}}}}} \right)$$

C. $$\frac{{{\text{f}}{\alpha _{{\text{CB}}}}}}{{1 - {\alpha _{{\text{CB}}}}}}$$

D. $$\frac{{\text{f}}}{{{\alpha _{{\text{CB}}}}}}$$

Answer: Option C

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