For a matrix \[\left[ {\text{M}} \right] = \left[ {\begin{array}{*{20}{c}} {\frac{3}{5}}&{\frac{4}{5}} \\ {\text{x}}&{\frac{3}{5}} \end{array}} \right],\] the transpose of the matrix is equal to the inverse of the matrix, [M]T = [M]-1. The value of x is given by
A. \[ - \frac{4}{5}\]
B. \[ - \frac{3}{5}\]
C. \[\frac{3}{5}\]
D. \[\frac{4}{5}\]
Answer: Option A
This Question Belongs to Engineering Maths >> Linear Algebra
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