For a reaction A ⟶ B, if the rate of change in concentration of A (CA), can be written as $$\frac{{ - dCA}}{{dt}} = k.C_A^2,$$ then the change concentration with time from initial concentration of A, Cao is given by
A. $$\left( {\frac{1}{{{C_A}}}} \right) - \left( {\frac{1}{{{C_{AO}}}}} \right) = K.t$$
B. (CAO - CA) = k.t
C. $$\left( {{C_{A{O^2}}} - C_A^2} \right) = k.t$$
D. $${\text{In}}\left( {\frac{{{C_{AO}}}}{{{C_A}}}} \right) = k.t$$
Answer: Option A
This Question Belongs to Metallurgical Engineering >> Metallurgical Thermodynamics And Kinetics
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