For a simply supported beam of span 15m, the minimum effective depth to satisfy the vertical deflection limits should be
A. 600 mm
B. 750 mm
C. 900 mm
D. More than 1 m
Answer: Option D
This Question Belongs to Civil Engineering >> Concrete Technology And Design Of Concrete Structures
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In symmetrically reinforced sections, shrinkage stresses in concrete and steel are respectively
A. Compressive and tensile
B. Tensile and compressive
C. Both compressive
D. Both tensile
Critical section for shear in case of flat slabs is (adopting standard notations)
A. At a distance of effective depth of slab from periphery of column/drop panel
B. At a distance of $$\frac{{\text{d}}}{2}$$ from periphery of column/capital/drop panel
C. At the drop panel of slab
D. At the periphery of column
A. depends on as, only
B. depends on aCbC only
C. depends on both crst and acbc
D. is independant of both ast and acbc where d is the effective depth, ast is per-missible stress in steel in tension and ocbc is permissible stress in concrete in bending compression.
The diameter of ties in a column should be
A. More than or equal to one fourth of diameter of main bar
B. More than or equal to 5 mm
C. More than 5 mm but less than one-fourth of diameter of main bar
D. More than 5 mm and also more than one-fourth of diameter of main bar
750mm
For >10m span,, span/depth = span^2/22x10=15x15/22x10=1.125>1m
if we have span greater than 15m then formula be like or you may can say verticle deflection may generally be satisfied as fallows
span2*2 ok...............
if we have span less than 10m then verticle deflection limit may satisfied as fallows
for cantiliver=7
for simply supported=20
for Continious=26
Ans should be..more than 1 m
Answer should be d
As Length is more than 10; which is 15
l/d = 20*(10/15)
d = (15*15)/(20*10) >1 m