For any integral value of n, 32n + 9n + 5 when divided by 3 will leave the remainder
A. 1
B. 2
D. 5
Answer: Option B
Solution (By Examveda Team)
32n + 9n + 5Put n = 1
⇒ 32 × 1 + 9 × 1 + 5
⇒ 9 + 9 + 5
⇒ 23 ⇒ $$\frac{{23}}{3}$$
⇒ remainder = 2
Note: value of n can be 1, 2, 3, 4, . . . . .
This Question Belongs to Arithmetic Ability >> Number System
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