For any integral value of n, 3²ⁿ + 9n + 5 when divided by 3 will leave the remainder

A. 1

B. 2

C. 0

D. 5

Answer: Option B

Solution(By Examveda Team)

3²ⁿ + 9n + 5
Put n = 1
⇒ 3^{2 × 1} + 9 × 1 + 5
⇒ 9 + 9 + 5
⇒ 23 ⇒ $$\frac{{23}}{3}$$
⇒ remainder = 2
Note: value of n can be 1, 2, 3, 4, . . . . .