For the same solid content, if the quantity of sludge with moisture content of 98% is X, then the quantity of sludge with moisture content of 96% will be
A. $$\frac{{\text{X}}}{4}$$
B. $$\frac{{\text{X}}}{2}$$
C. X
D. 2X
Answer: Option B
This Question Belongs to Civil Engineering >> Environmental Engineering
Join The Discussion
Comments ( 2 )
Related Questions on Environmental Engineering
The distribution mains are designed for
A. Maximum daily demand
B. Maximum hourly demand
C. Average daily demand
D. Maximum hourly demand on maximum day
Sewage treatment units are designed for
A. Maximum flow only
B. Minimum flow only
C. Average flow only
D. Maximum and minimum flow
A. 4.5 to 6.0
B. 6.5 to 8.0
C. 8.5 to 10.0
D. 10.5 to 12.0
As we know that, in a sludge digestion tank for different moisture content in the sludge the volumes are will be different and follows the below equations:
V1/V2=100-P1/100-P2
98% water content produces 2 kg of sludge and 9% water content produces 4 kg of sludge, if x = 2kg then relation will be 2X.