$$\frac{{2\sin \theta }}{{\cos \theta \left( {1 + {\text{ta}}{{\text{n}}^2}\theta } \right)}}$$ simplifies to?
A. cosθ
B. cos2θ
C. sin2θ
D. sinθ
Answer: Option C
Solution (By Examveda Team)
$$\eqalign{ & = \frac{{2\sin \theta }}{{\cos \theta \left( {1 + {\text{ta}}{{\text{n}}^2}\theta } \right)}} \cr & = \frac{{2{\text{tan}}\theta }}{{1 + {\text{ta}}{{\text{n}}^2}\theta }} \cr & = \sin2\theta \cr} $$This Question Belongs to Arithmetic Ability >> Trigonometry
Question option and solution updated, thanks for reporting error, @Subrat Das
Sin 2 theta not sin^2theta