$$\frac{{2\sin \theta }}{{\cos \theta \left( {1 + {\text{ta}}{{\text{n}}^2}\theta } \right)}}$$     simplifies to?

A. cosθ

B. cos2θ

C. sin2θ

D. sinθ

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & = \frac{{2\sin \theta }}{{\cos \theta \left( {1 + {\text{ta}}{{\text{n}}^2}\theta } \right)}} \cr & = \frac{{2{\text{tan}}\theta }}{{1 + {\text{ta}}{{\text{n}}^2}\theta }} \cr & = \sin2\theta \cr} $$