$$\frac{5}{9}$$ part of the population in a village are males. If 30% of the males are married, the percentage of unmarried females in the total population is :
A. 20%
B. $$27\frac{7}{9}$$%
C. 40%
D. 70%
Answer: Option B
Solution(By Examveda Team)
Let total population = xThen, number of males = $$\frac{5}{9}$$x
Married males :
= 30% of $$\frac{5}{9}$$x
= $$\frac{30}{100}$$ × $$\frac{5}{9}$$x
= $$\frac{x}{6}$$
Married females = $$\frac{x}{6}$$;
Number of females :
= x - $$\frac{5}{9}$$x
= $$\frac{4x}{9}$$
Unmarried females :
= $$\frac{4x}{9}$$ - $$\frac{x}{6}$$
= $$\frac{5x}{18}$$
∴ Required percentage :
= $$\frac{5x}{18}$$ × $$\frac{1}{x}$$ × 100%
= $$27\frac{7}{9}$$%
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