From Arhenius law, a plot of loge K versus $$\frac{1}{{\text{T}}}$$ gives a straight line with a slope of $$\left( { - \frac{{\text{E}}}{{\text{R}}}} \right)$$ . The unit of $$\frac{{\text{E}}}{{\text{R}}}$$ is
A. K cal
B. K cal/°K
C. °K
D. K cal. °K
Answer: Option C

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