Geeta runs $$\frac{5}{2}$$ times as fast as Babita. In a race, if Geeta gives a lead of 40 m to Babita, find the distance from the starting point where both of them will meet (correct up to two decimal places).

Solution (By Examveda Team)

$$\eqalign{ & {\text{Babita's speed}} = 1 \cr & {\text{Geeta's speed}} = \frac{5}{2} \cr} $$

$$\eqalign{ & \Rightarrow {\text{Relative speed in same direction}} \cr & = \frac{5}{2} - 1 = \frac{3}{2} \cr & \Rightarrow {\text{Time}} = \frac{{40}}{{\frac{3}{2}}} = \frac{{80}}{3} = 26.66 \cr & {\text{Distance travel by Babita}} \cr & = 1 \times 26.66\, - - - - - \,26.66 \cr & {\text{Total distance}} = 40 + 26.66 \cr & = 66.66 \cr & = 66.67 \cr} $$