Given that (12 + 22 + 32 + ..... + 202) = 2870, the value of (22 + 42 + 62 + ... + 402 ) is :
A. 2870
B. 5740
C. 11480
D. 28700
Answer: Option C
Solution (By Examveda Team)
= (22 +42 +62 + ..... + 402)= (1 × 2)2 +(2 × 2)2 +(2 × 3)2 + ..... + (2 × 20)2
= 22 × (12 + 22 + 32 + ..... + 202)
= (4 × 2870)
= 11480
This Question Belongs to Arithmetic Ability >> Number System
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