Examveda
Examveda

Half life period of decomposition of a liquid 'A' by irreversible first order reaction is 12 minutes. The time required for 75% conversion of 'A' is __________ minutes.

A. 18

B. 24

C. 6

D. 12

Answer: Option B


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Comments ( 1 )

  1. Chintan Bhalerao
    Chintan Bhalerao :
    3 years ago

    for first order reaction half life period is given by:
    t1/2 = 0.693/K
    so we have half time so by solving this equation calculate K which will be 0.05775 min^-1
    now for first order irreversible equation the equation for calculating rate constant is
    K = (1/T)*ln(CA0/CA)
    CA = 0.25 and CA0 = 1
    So by solving we will get t = 24 minutes
    Thank you

Related Questions on Chemical Reaction Engineering

A first order gaseous phase reaction is catalysed by a non-porous solid. The kinetic rate constant and the external mass transfer co-efficients are k and $${{\text{k}}_{\text{g}}}$$ respectively. The effective rate constant (keff) is given by

A. $${{\text{k}}_{\text{e}}}{\text{ff}} = {\text{k}} + {{\text{k}}_{\text{g}}}$$

B. $${{\text{k}}_{\text{e}}}{\text{ff}} = \frac{{{\text{k}} + {{\text{k}}_{\text{g}}}}}{2}$$

C. $${{\text{k}}_{\text{e}}}{\text{ff}} = {\left( {{\text{k}}{{\text{k}}_{\text{g}}}} \right)^{\frac{1}{2}}}$$

D. $$\frac{1}{{{{\text{k}}_{\text{e}}}{\text{ff}}}} = \frac{1}{{\text{k}}} + \frac{1}{{{{\text{k}}_{\text{g}}}}}$$