HCF of $$\frac{2}{3}{\text{,}}\frac{4}{5}$$  and $$\frac{6}{7}$$ is = ?

A. $$\frac{{48}}{{105}}$$

B. $$\frac{2}{{105}}$$

C. $$\frac{1}{{105}}$$

D. $$\frac{{24}}{{105}}$$

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & {\text{HCF of fractional number is}} \cr & = \left( {\frac{{{\text{HCF of numerator}}}}{{{\text{LCM of Denominator}}}}} \right) \cr & \therefore {\text{HCF }}\left( {\frac{2}{3},\frac{4}{5},\frac{6}{7}} \right) \cr & \Rightarrow \left( {\frac{{{\text{HCF of 2,4,6}}}}{{{\text{LCM of 3,5,7}}}}} \right) \cr & \Rightarrow \frac{2}{{3 \times 5 \times 7}} \cr & \Rightarrow \frac{2}{{105}} \cr} $$