Examveda
Examveda

Heat capacity of air can be approximately expressed as, Cp = 26.693 + 7.365 × 10-3 T, where, Cp is in J/mole.K and T is in K. The heat given off by 1 mole of air when cooled at atmospheric pressure from 500°C to -100°C is

A. 10.73 kJ

B. 16.15 kJ

C. 18.11 kJ

D. 18.33 kJ

Answer: Option C


This Question Belongs to Chemical Engineering >> Stoichiometry

Join The Discussion

Comments ( 1 )

  1. Mayank Chauhan
    Mayank Chauhan :
    3 years ago

    As specific heat is not constant , we have to integrate the term with respect to dt
    Change in Enthalpy ( molar) = integration (Cp)dt
    Answer : 18.11 kJ

Related Questions on Stoichiometry