The total number of atoms in 8.5 gm of NH3 is __________ × 1023.
A. 9.03
B. 3.01
C. 1.204
D. 6.02
Answer: Option A
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Related Questions on Stoichiometry
A. Potential energy
B. Intermolecular forces
C. Kinetic energy
D. Total energy
A. ΔH = 1 (+ ve)and Δ V = -ve
B. ΔH = 0
C. ΔV = 0
D. Both B and C
12.o4 option c.. no one is right however
3.01*4=12.04
3.01 are molecules and four atoms present there. one N and three H. multiplying both gives total nmber of atoms
The molar mass of NH3 is equals to 17 gram.
Moles of NH3 in 8.5 gm =8.5/17=0.5
thus molecules in half mole NH3 is 6.022×10^23×0.5
and atoms in half mole NH3=0.5× 6.022×10^23×4
now calculate it
I think this is wrong .. Cause ... Guiven mass /molar mass*6.02*10^23 * atoms is the formula
= 8.5/17×6.02×10^23× 4 [1 H & 3N]
=3.01×4 = 12.04.m option B should be ri8 .. Printing mistake..
Wrong ans
Correct answer is B.
No.of moles of NH3= 8.5/17 =0.5
1mole = 6.022×10^23 atoms
0.5mole= 0.5×6.022×10^23=3.011×10^23
Any one explain this pb
Please explain the solution.