How many pairs of natural numbers is there the difference of whose squares are 45.
A. 1
B. 2
C. 3
D. 4
E. 5
Answer: Option C
Solution (By Examveda Team)
(x2 - y2) = 45 Or, (x - y)(x + y) = 45 Thus, the factors of 45 possibles are 15, 3, 9, 5, 1 and 45 Hence, numbers are 9 and 6 or 7 and 2 or 23 and 22So, number of such pairs = 3
This Question Belongs to Arithmetic Ability >> Number System
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