I had Rs. 10000 with me. Out of this money I lent some money to A for 2 years @ 15% simple interest. I lent the remaining money to B for an equal number of years @18% simple interest. After 2 years, I found that A had given me Rs. 360 more as interest as compared to B. The amount of money which I had lent to B must have been.
A. Rs. 2000
B. Rs. 3000
C. Rs. 4000
D. Rs. 5000
Answer: Option C
Solution(By Examveda Team)
Let the sum lent to A be Rs. x. and that lent to B be Rs. (10000 - x)Then,
$$\eqalign{ & \Rightarrow \frac{{x \times 15 \times 2}}{{100}} - \frac{{\left( {10000 - x} \right) \times 18 \times 12}}{{100}} = 360 \cr & \Rightarrow 30x - 360000 + 36x = 36000 \cr & \Rightarrow 66x = 396000 \cr & \Rightarrow x = 6000 \cr} $$
Hence,
Sum lent to B
= Rs. (10000 - 6000)
= Rs. 4000
Related Questions on Interest
Find the simple interest on Rs. 5200 for 2 years at 6% per annum.
A. Rs. 450
B. Rs. 524
C. Rs. 600
D. Rs. 624
Rs. 1200 is lent out at 5% per annum simple interest for 3 years. Find the amount after 3 years.
A. Rs. 1380
B. Rs. 1290
C. Rs. 1470
D. Rs.1200
E. Rs. 1240
Interest obtained on a sum of Rs. 5000 for 3 years is Rs. 1500. Find the rate percent.
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B. 9%
C. 10%
D. 11%
E. 12%
Rs. 2100 is lent at compound interest of 5% per annum for 2 years. Find the amount after two years.
A. Rs. 2300
B. Rs. 2315.25
C. Rs. 2310
D. Rs. 2320
E. None of these
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