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If θ is positive acute angle and 3(sec2θ + tan2θ) = 5, then the value of cos2θ is?
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& {\text{3}}\left( {{{\sec }^2}\theta + {\text{ta}}{{\text{n}}^2}\theta } \right) = 5 \cr
& {\sec ^2}\theta + {\text{ta}}{{\text{n}}^2}\theta = \frac{5}{3}\,.....(i) \cr
& {\sec ^2}\theta - {\text{ta}}{{\text{n}}^2}\theta = 1\,......(ii) \cr
& {\text{Adding equation (i) and (ii)}} \cr
& {\text{2}}{\sec ^2}\theta = \frac{8}{3} \cr
& sec\theta = \frac{2}{{\sqrt 3 }} \cr
& \therefore \theta = {30^ \circ } \cr
& \cos 2\theta = \cos 2\left( {{{30}^ \circ }} \right) \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \cos {60^ \circ } \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{1}{2} \cr} $$
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