If 1 + sin2θ - 3sinθcosθ = 0, then the value of cotθ is:
A. 2
B. $$\frac{1}{3}$$
C. $$\frac{1}{2}$$
Answer: Option A
Solution (By Examveda Team)
1 + sin2θ - 3sinθ.cosθ = 0⇒ 1 - 2sinθ.cosθ = sinθ.cosθ - sin2θ
⇒ sin2θ + cos2θ - 2sinθ.cosθ = sinθ(cosθ - sinθ)
⇒ (cosθ - sinθ)2 = sinθ(cosθ - sinθ)
⇒ cosθ - sinθ = sinθ
⇒ cosθ = 2sinθ
⇒ cotθ = 2
This Question Belongs to Arithmetic Ability >> Trigonometry
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