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If $$\frac{1}{{x + \frac{1}{{y + \frac{2}{{z + \frac{1}{4}}}}}}} = \frac{{29}}{{79}},$$ where x, y and z are natural numbers, then the value of (2x + 3y - z) is:
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& \frac{1}{{x + \frac{1}{{y + \frac{2}{{z + \frac{1}{4}}}}}}} = \frac{{29}}{{79}} \cr
& \frac{1}{{2 + \frac{1}{{1 + \frac{2}{{5 + \frac{1}{4}}}}}}} = \frac{{29}}{{79}} \cr
& x = 2,\,y = 1,\,z = 5 \cr
& \left( {2x + 3y - z} \right) \cr
& = 2 \times 2 + 3 \times 1 - 5 \cr
& = 2 \cr} $$
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