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If 750 µA is flowing through 11 kΩ of resistance, what is the voltage drop across the resistor?

A. 8.25 V

B. 82.5 V

C. 14.6 V

D. 146 V

Answer: Option A


This Question Belongs to Electrical Engineering >> Ohms Law

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Comments ( 1 )

  1. Mousumi Saikia
    Mousumi Saikia :
    4 years ago

    I= .75A
    R= 11 kohm
    Therefor
    Voltage drop= .75*11
    = 8.25v

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