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This question belongs to Electrical Engineering Ohms Law
Ohms Law
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If 750 µA is flowing through 11 kΩ of resistance, what is the voltage drop across the resistor?

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Correct Answer: Option A
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Mousumi Saikia
Mousumi Saikia 6 years ago
I= .75A
R= 11 kohm
Therefor
Voltage drop= .75*11
= 8.25v