If $${\text{A}} = \left[ {\frac{3}{7}{\text{ of }}4\frac{1}{5} \div \frac{{18}}{{25}} + \frac{{17}}{{24}}} \right]{\text{ of }}\left[ {\frac{{289}}{{16}} \div {{\left( {\frac{3}{4} + \frac{2}{3}} \right)}^2}} \right],$$          then the value of 8A is:

Solution(By Examveda Team)

$$\eqalign{ & {\text{A}} = \left[ {\frac{3}{7}{\text{ of }}4\frac{1}{5} \div \frac{{18}}{{25}} + \frac{{17}}{{24}}} \right]{\text{ of }}\left[ {\frac{{289}}{{16}} \div {{\left( {\frac{3}{4} + \frac{2}{3}} \right)}^2}} \right] \cr & {\text{A}} = \left[ {\frac{3}{7}{\text{ of }}\frac{{21}}{5} \div \frac{{18}}{{25}} + \frac{{17}}{{24}}} \right]{\text{ of }}\left[ {\frac{{289}}{{16}} \div \frac{{{{17}^2}}}{{{{12}^2}}}} \right] \cr & {\text{A}} = \left[ {\frac{9}{5} \times \frac{{25}}{{18}} + \frac{{17}}{{24}}} \right]{\text{ of }}\left[ {\frac{{289}}{{16}} \times \frac{{144}}{{289}}} \right] \cr & {\text{A}} = \left[ {\frac{5}{2} + \frac{{17}}{{24}}} \right]{\text{ of 9}} \cr & {\text{A}} = \frac{{77}}{{24}} \times 9 \cr & {\text{8A}} = 8 \times \frac{{77}}{{24}} \times 9 \cr & {\text{8A}} = 231 \cr} $$