If a, b and c are positive numbers such that (a2 + b2) : (b2 + c2) : (c2 + a2) = 34 : 61 : 45, then b - a : c - b : c - a = . . . . . . .
A. 3 : 1 : 2
B. 3 : 2 : 1
C. 1 : 2 : 3
D. 2 : 1 : 3
Answer: Option D
Solution(By Examveda Team)
(a2 + b2) : (b2 + c2) : (c2 + a2) = 34 : 61 : 45Add all
2(a2 + b2 + c2) = 34 + 61 + 45
2(a2 + b2 + c2) = 140
(a2 + b2 + c2) = 70
c2 = 70 - 34
c2 = 36
c = 6
b2 = 70 - 45
b2 = 25
b = 5
a2 = 70 - 61
a2 = 9
a = 3
(b - a) : (c - b) : (c - a)
= (5 - 3) : (6 - 5) : (6 - 3)
= 2 : 1 : 3
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