If \[{\text{A}} = \left[ {\begin{array}{*{20}{c}} 1&5 \\ 6&2 \end{array}} \right]\] and \[{\text{B}} = \left[ {\begin{array}{*{20}{c}} 3&7 \\ 8&4 \end{array}} \right],\,{\text{A}}{{\text{B}}^{\text{T}}}\] is equal to
A. \[\left[ {\begin{array}{*{20}{c}} {38}&{28} \\ {32}&{56} \end{array}} \right]\]
B. \[\left[ {\begin{array}{*{20}{c}} 3&{40} \\ {42}&8 \end{array}} \right]\]
C. \[\left[ {\begin{array}{*{20}{c}} {43}&{27} \\ {34}&{50} \end{array}} \right]\]
D. \[\left[ {\begin{array}{*{20}{c}} {38}&{32} \\ {28}&{56} \end{array}} \right]\]
Answer: Option A
This Question Belongs to Engineering Maths >> Linear Algebra
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