If a is the optimistic time, b is the pessimistic time and m is most likely time of an activity, the expected time of the activity, is
A. $$\frac{{{\text{a}} + {\text{m}} + {\text{b}}}}{6}$$
B. $$\frac{{{\text{a}} + 2{\text{m}} + {\text{b}}}}{6}$$
C. $$\frac{{{\text{a}} + 4{\text{m}} + {\text{b}}}}{6}$$
D. $$\frac{{{\text{a}} + 5{\text{m}} + {\text{b}}}}{6}$$
Answer: Option C

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