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If $${\text{a}} = {\text{lo}}{{\text{g}}_{\text{8}}}\,{\text{225}}$$ and $${\text{b = lo}}{{\text{g}}_{\text{2}}}\,{\text{15}},$$ then a in terms of b is -
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& a = {\log _8}225 \cr
& = {\log _{{2^3}}}\left( {{{15}^2}} \right) \cr
& = \frac{2}{3}{\log _2}15 \cr
& = \frac{{2b}}{3} \cr} $$
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