?
$${{\log \sqrt 8 } \over {\log 8}}$$ is equal to:
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& \frac{{\log \sqrt 8 }}{{\log 8}} = {\frac{{\log \left( 8 \right)}}{{\log 8}}^{\frac{1}{2}}} \cr
& = \frac{{\frac{1}{2}\log 8}}{{\log 8}} \cr
& = \frac{1}{2} \cr} $$
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