If a matrix \[{\text{A}} = \left[ {\begin{array}{*{20}{c}} 2&4 \\ 1&3 \end{array}} \right]\] and matrix \[{\text{B}} = \left[ {\begin{array}{*{20}{c}} 4&6 \\ 5&9 \end{array}} \right]\] the transpose of product of these two matrices i.e., (AB)T is
A. \[\left[ {\begin{array}{*{20}{c}} {28}&{19} \\ {34}&{47} \end{array}} \right]\]
B. \[\left[ {\begin{array}{*{20}{c}} {19}&{34} \\ {47}&{28} \end{array}} \right]\]
C. \[\left[ {\begin{array}{*{20}{c}} {48}&{33} \\ {28}&{19} \end{array}} \right]\]
D. \[\left[ {\begin{array}{*{20}{c}} {28}&{19} \\ {48}&{33} \end{array}} \right]\]
Answer: Option D
This Question Belongs to Engineering Maths >> Linear Algebra
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