?
If ax = by, then:
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& {a^x} = {b^y} \cr
& \Rightarrow \log {a^x} = \log {b^y} \cr
& \Rightarrow x\log a = y\log b \cr
& \Rightarrow {{\log a} \over {\log b}} = {y \over x} \cr} $$
Join the Discussion
Login to post a comment or share your explanation.
Login