If B is the width of formation, d is the height of the embankment, side slope S : 1, for a highway with no transverse slope, the area of cross-section is
A. $${\text{B}} + {\text{d}} + {\text{Sd}}$$
B. $${\text{Bd}} + {\text{S}}{{\text{d}}^2}$$
C. $${\text{B}} \times {\text{d}} - {\text{S}}{{\text{d}}^{\frac{1}{2}}}$$
D. $$\frac{1}{2}\left( {{\text{Bd}} + {\text{S}}{{\text{d}}^2}} \right)$$
Answer: Option B
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Give data
Width=B
Height=d
Slope =S:1
What is the base of triangle..?
Slope = height/ base or rise/ run
Slope=S/1= d/base
n base = d
base=d/n
Area of cross-section= Area of rectangle+ Area of triangle
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AREA OF CROSS SECTION =Area of rectangle + 2* Area of triangle.
=BD+SD^2.
In case of cutting side slope is 1:1.
In case of Filling side slope is 2:1 (H:V).
How??