If cosA + cosB + cosC = 3, then what is the value of sinA + sinB + sinC?
A. 1
B. 2
D. -1
Answer: Option C
Solution (By Examveda Team)
cosA + cosB + cosC = 3⇒ putting A, B, C = 0
1 + 1 + 1 = 3
3 = 3 Satisfied
So, sinA + sinB + sinC
= sin0° + sin0° + sin0°
= 0 + 0 + 0
= 0
This Question Belongs to Arithmetic Ability >> Trigonometry
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